Concrete Abstractions: Chapter 8

Exercise 8.1: Write a procedure called minimum that will find the smallest element in a nonempty binary search tree of numbers.

Solution:

Exercise 8.2: Write a procedure called number-of-nodes that will count the number of elements in a binary search tree.

Solution:

Exercise 8.6: Suppose we want to create a new binary search tree by adding another element to an already existing binary search tree. Where is the easiest place to add such an element? Write a procedure called insert that takes a number and a binary search tree of numbers and returns a new binary search tree whose elements consist of the given number together with all of the elements of the binary search tree. You may assume that the given number isn’t already in the tree.

Solution:

Exercise 8.7: Using the procedure insert, write a procedure called list->bstree that takes a list of numbers and returns a binary tree whose elements are those numbers. Try this on several different lists and draw the corresponding tree diagrams. What kind of list gives you a short bushy tree? What kind of list gives a tall skinny tree?

Solution:

Exercise 8.11: In many applications, binary trees aren’t sufficient because we need more than two subtrees. An m-ary tree is a tree that is either empty or has a root and m subtrees, each of which is an m-ary tree. Generalize the previous results to m-ary trees.

Solution:
Ok. So let’s see if we can find a formular for 3-ary trees first.

So we can see that a tree with an height of two has 3^2 + 3^1 + 3^0 nodes. Or more general: A 3-ary tree with an height of n has sum_{i=0}^{n} 3^i nodes. This can be simplified as frac{1 - 3^{n+1}}{1-3}. So is this true? Let’s see. The height should be n. What’s happening if we increase the height by one? Each leave will get three children. We assumed that there are 3^n leaves. Therefore there will be 3^n * 3 = 3^{n+1} children. That is, there will be at most text{nodes}(n+1) = text{nodes}(n) + 3^{n+1} nodes which is equivalent to sum_{i=0}^{n} 3^i + 3^{n+1} = sum_{i=0}^{n+1} 3^i.
Therefore there are sum_{i=0}^{n} m^i nodes in a m-ary of height n.

Exercise 8.12: In Exercise 8.7, you wrote a procedure list->bstree that created a binary search tree from a list by successively inserting the elements into the tree. This procedure can lead to trees that are far from minimum height—surprisingly, the worst case occurs if the list is in sorted order. However, if you know the list is already in sorted order, you can do much better: Write a procedure sorted-list->min-height-bstree that creates a minimum height binary search tree from a sorted list of numbers. Hint: If the list has more than one element, split it into three parts: the middle element, the elements before the middle element, and the elements after. Construct the whole tree by making the appropriate recursive calls on these sublists and combining the results.

Solution:

Exercise 8.31: Write a procedure that takes as arguments a binary search tree of numbers, a lower bound, and an upper bound and counts how many elements of the tree are greater than or equal to the lower bound and less than or equal to the upper bound. Assume that the tree may contain duplicate elements. Make sure your procedure doesn’t examine more of the tree than is necessary.

Solution:

#85/111: Machine Learning

The book

This is probably one of the standard intro texts into machine learning. Tom Mitchell covers most of the basic techniques in machine learning (ToC) but doesn’t cover all of them, e.g. SVMs. I got a bit of background in statistics so it was rather easy to dive into machine learning although their terminology is a mostly different from statistics.

If you don’t have a background in statistics but solid basics in calculus then it should be rather easy to understand the contents of this book. There are lots of exercises which help you to strengthen your understanding. I think it’s an ideal theoretical basis for Programming Collective Intelligence. All in all, a really nice book if you are interested in machine learning.

SPOJ: 1728. Common Permutation

Given two strings of lowercase letters, a and b, print the longest string x of lowercase letters such that there is a permutation of x that is a subsequence of a and there is a permutation of x that is a subsequence of b.

Problem: Sphere Online Judge (SPOJ) – Problem CPRMT

Solution: That’s short and nice problem. You have to find all letters which are in both strings. I’d actually like to see some other implementations of this. I bet there are some languages which handle this in a smart way.

#84/111: R in a Nutshell

Intro

So, I read a few more technical books and asked myself how I should present them. I came to the conclusion that writing a summary and stuff isn’t really practical. Therefore I will only post a small entry with some words about the book. However, if you want to know more about a specific book and don’t find enough stuff about it online, you can ask me about it.

The book

I looked for a nice intro to R because the official documentations is a bit too meta. What I found is this book which is a great reference and introduction to R. Joseph Adler covers the whole bandwidth of topics from data cleansing to analysis and graphics. He even covers 3th party packages for bioinformatics. However, if you don’t have a clue about statistics you should firstly read some books about it. This book doesn’t cover any proofs or derivations of statistical methods. All in all a pretty nice book which doesn’t have any serious flaws.